Sometimes it's useful to have a method for generating unique numbers that are uniformly distributes over some set. For example, we may have a collection of objects that need to be identified uniquely, and serve as a key to an associative container.

It isn't always desired to use monotonically-increasing counter - for example, if we were to store our objects in an unbalanced tree, we would end up with a degenerate, inefficient, tree. In small or embedded applications, it is sometimes easier to implement a simple unbalanced tree and have the keys be uniformaly distributed than implement a red-black or AVL tree.

A simple and efficient method that guarentees uniqueness, as well as randomness, is to use an LFSR. There are many known maximal-length LFSRs, which guarantee that if an LFSR has a state of n bits (and the initial state is not all-zeros) we can advance the LFSR 2n-1 times before we get any state we already seen. In other words, if an LFSR describes a chain of states, a maximal-length LFSR gurantees there is a single loop for all possible states.

There are a few standartized maxima-length LFSRs being used by the industry: the PRBS sequences. These sequnces are commonly used in communcation equipment testing, because they allow testing of all possible bit-patterns as quickly as possible (and it's also very easy to detect a defective PRBS sequence, indicating transmission or reception errors).

Let's assume that we need to choose unique and randomly distributed 32-bit integers. A leading candidate would be PRBS31 (x31+x28+1). Implementation is failry simple:

public int prbs31(int state) {
    int feedback = ((state >> 30) ^ (state >> 27)) & 1;
    return ((state << 1) | feedback) & 0xffffffff;
We simply XOR the LFSR's taps, shift the state and push the feedback.

Note that due to the LFSR's nature, adjancent values will be very similar (they differ by one shift and one bit, so for every state Nk we have: Nk+1∈{2Nk mod 2n, 2Nk+1 mod 2n}).

To get "non-similar" values, we can just call prbs31 successively, like so:

// initial seed, doesn't really matter which value you use
// as long as it's not zero (remember that the sequence goes over
// all the possible 31-bits values anyway)
private static final int SEED = 0x55555555;

private int state = SEED;

public int nextInt() throws SequenceCycleException {
    for (int i = 0; i < 31; ++i) {
        state = prbs31(state);
        if (state == SEED) {
            throw new SequenceCycleException();
    return state;

DISCLAIMER: naive usage of a single LFSR is highly predictable. In this case, knowing one value gives knowledge of all future values - which makes this method good for simulations (such as games) but also very bad for anything with cryptographic or secret significance!

I originally gave this method as an answer in a Stack Overflow question.